x + y = 9x + y9x + y = x + y8x + y = y8x = 0x = 0
The example, y = 8x + 16, is in slope-intercept form, the easiest to graph. First, you plot the point (0,16) because 16 is the plain number being added, the y intercept. Going from that point, you draw a line with slope 8. This means that, from the intercept, you draw a line that goes right 1 box, and up 8 boxes. Once you figure out what it looks like, you can continue the line without counting. This is a steep line.
The expression of y8x-9 has no solution because without an equality sign it can not be considered to be an equation.
linear
x + y = 9x + y9x + y = x + y8x + y = y8x = 0x = 0
If you mean: y = 8x-6 then the gradient is 8 and the y intercept is -6
If you mean: y = 8x+3 containing point (5,7) Then perpendicular equation is: y-7 = -1/8(x-5) => 8y = -x+61
The example, y = 8x + 16, is in slope-intercept form, the easiest to graph. First, you plot the point (0,16) because 16 is the plain number being added, the y intercept. Going from that point, you draw a line with slope 8. This means that, from the intercept, you draw a line that goes right 1 box, and up 8 boxes. Once you figure out what it looks like, you can continue the line without counting. This is a steep line.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (eg x-squared = x^2). However, let's answer for the two lines with equations y = 8x - 10 and y - 4x = 20. Let's use the substitution method. Substitute y with 8x - 10 to the second equation. 8x - 10 - 4x = 20 4x = 30 x = 30/4= 15/2 (the x-coordinate of the intersection point) y = 8x - 10 replace 15/2 for x y = 8(15/2) - 10 = 50 (the y-coordinate of the intersection point) So the two lines intersect at (15/2, 50).