To divide ( y ) by the numbers 7, 6, and 11, you can express it as ( \frac{y}{7 \times 6 \times 11} ). First, calculate the product of the divisors: ( 7 \times 6 = 42 ) and then ( 42 \times 11 = 462 ). Therefore, ( y ) divided by 7, 6, and 11 is ( \frac{y}{462} ).
y=3.5
y divided by 7 is y/7 7 divided by y is 7/y
3/Y+7\Y=9 =>Y=10\9
11
5y-7 = 2y+11 (+7 to both sides) 5y = 2y+18 (- 2y from both sides) 3y = 18 (divide both sides by 3 ) y = 6 y=6
Solving the equations y/7 +6 = 11 Subtract 6 from both sides: y/7 = 5 multiply both sides by 7: 7 = 35
y/7 + 6 = 11 Subract 6 from bot sides: y/7 = 11 - 6 = 5 Multiply both sides by 7: y = 5*7 = 35
y=3.5
y divided by 7 is y/7 7 divided by y is 7/y
42 divided by 7 is 6. 7y = 42 Divide both sides by 7. y = 6.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals".There is no symbol between 5x and y.
3/Y+7\Y=9 =>Y=10\9
-1
1 divided y equils 6 = 0.16666666666666666
11
5y-7 = 2y+11 (+7 to both sides) 5y = 2y+18 (- 2y from both sides) 3y = 18 (divide both sides by 3 ) y = 6 y=6
x = -6 and y = 1