Just simply set x equal to 0 in the original equation, and solve for y. Then set y equal to 0 in the original equation and solve for x. When you solve for x, you put that answer for the x coordinate, and a 0 for the y coordinate, and when you solve for y, you put that answer in for the y coordinate, and a 0 for the x coordinate.
Let x=0 in y=-6x+9
y=-6(0)+9
y=0+9
y=9
Now put a 9 for your y coordinate, and a 0 for your x coordinate.
(0,9).
Let y=0.
y=-6x+9
0=-6x+9
Subtract 9 on both sides.
0-9=-6x+9-9
-6x=-9
Divide by -6 on each side.
(-6x)/-6=-9/-6
x=1.5
Now put a 1.5 for your x coordinate, and a 0 for your y coordinate.
(1.5,0).
Your final answers are (0,9) and (1.5,0).
one
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
-6x
-3
-3
-6x + y = 9 (+6x) -> y = 6x + 9
one
-3
-3
Put in function, Y = mX + C, form. 6X + 3Y = - 9 3Y = - 6X - 9 Y = - 2X - 3 -------------------- m(slope) = - 2 ----------------------
y=6x-16 y=-2x+8
Well, f(x) = 6x + 9 is a function of x {it passes the vertical line test}. but y = 6x + 9 is an equation {linear equation of two variables}
y = x2 - 6x + 2 y = x2 - 6x + 9 - 7 y = (x - 3)2 - 7
-6x
y=9
6x+3y = -9 3y = -6x-9 y = -2x-3 Therefore the perpendicular slope is 1/2
-3