Yes.
No. It is a linear equation (y = 5/2 x + 5). A quadratic equation requires a squared term, for example y = x2 + 5x + 6; this can be solved for x given y = 0, as in solving x2 + 5x + 6 = 0.
It is a quadratic equation in the variable x.
It has no solutions because the discriminant of the quadratic equation is less than zero.
The question contains two equations:5x - 6y = 15 5x + y = 2 There are no inequalities in the question.
Yes.
No. It is a linear equation (y = 5/2 x + 5). A quadratic equation requires a squared term, for example y = x2 + 5x + 6; this can be solved for x given y = 0, as in solving x2 + 5x + 6 = 0.
It is a quadratic equation in the variable x.
yes it is!
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
It is a linear equation in one variable.
It has no solutions because the discriminant of the quadratic equation is less than zero.
The question contains two equations:5x - 6y = 15 5x + y = 2 There are no inequalities in the question.
It is, as stated, x2 - 5x + 25/4 = 0
Doesn't have integer roots. Quadratic formula gives roots as 3.71 and -5.38.
It is a quadratic equation and its solutions are: x = 4 or x = -9
It is: 3x2-5x-2 = 0 and the value of x is -1/3 or 2 when solved