X intercept = -4 Y intercept = 2
y = -x + 8
11
x-intercept = -21y-intercept = 168
-6
Set y = 0 -x = 8 so that x = -8 is the x-intercept. Set x = 0 2y = 8 so that y = 4 is the y-intercept.
Add 8 to the x value, so f.e. If x=4, the y intercept = 4+8 =12 No, the y intercept is the value of y when the value of x = 0, so the y intercept of the equation is 8. In the general form y = mx + b, b will always be the y intercept.
-11
y=x+8 is a linear equation. Y is the Y point on a graph, X is the slope, and 8 is the y intercept
-4x + y = 8At the x-intercept, 'y' is zero.-4x = 8-x = 2x = -2At the y-intercept, 'x' is zero.y = 8
X intercept = -4 Y intercept = 2
y = -x + 8
11
y=-x+8
2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
Slope is -1 y-intercept is 1 x-intercept is 1
You state that y + x = -8 The y intercept is where x = 0 so replace that in the formula: y + 0 = -8 So the y intercept is at -8 ... (0, -8) is the point you're looking for.