8y/y + 2 + 16/y + 2 = 8 + 2 + 16/y +2 = 12 + 16/y = 4(3 + 4/y) or 4/y*(3y + 4)
y/9 - 2/5 = 1/3 => y = 6 3/5 or 6.6
5Y + 4/20
y= 1/2x - 2/3
change the y value to -y, and bring the negative over the equal sign. example. y=2x^2 reflected on the x-axis looks like y=(2x^2)/-1 which is equal to y=-(2x^2)
Of course. These are straight lines. Y = 5/2 Y = 2/5
2 halves or 1 whole.
An equation where Y = -7
y=x+2/4 (x+2 is all over four)
(2y-4)/(y+3)=(2-y-2)/(y+3) --> multiply both sides by (y+3) 2y-4=2-y-2 --> 2-2=0 (right hand side) 2y-4=-y --> add y to both sides 3y-4=0 --> add 4 to both sides 3y=4 --> divide both sides by 3 y=4/3
(-2,3) reflected over y = x is (3,-2) (400,-2) reflected over y = x is (-2,400) All you do is switch the ordered pair.
x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.
y=x+2/4 (x+2 is all over four)
the answer is -33/4 or -8.25
If: y = -2/3x+2 then the slope is -2/3 and the y intercept is 2
No, it is not.
It is: 5/9x-y+2 = 0