Question is y+12=? where value of y is 29.
y+12 = 29+12 = 41
The answer is 41.
y^2 + 7y + 12 = (y+4)(y+3)
If: 30y = 10+y Then: y = 10/29
It is: y = -4x+12
12 + 14 + 3 = 29
Y = 1 3(1) = 3 26 + 3 = 29
if y = 29 then 12+y = 41
y^2 + 7y + 12 = (y+4)(y+3)
-29
Y=29+5x+1 Y=30+5x Y-30=5x X=(Y-30)/5 That's about it...
If: 30y = 10+y Then: y = 10/29
1+12=13+15=28+2=30+29=59.
It is: y = -4x+12
12 + 14 + 3 = 29
-65
Y = 1 3(1) = 3 26 + 3 = 29
56
41