To calculate speed, divide the distance traveled by the time taken. Here, the speed would be ( 7564 \text{ km} \div 23 \text{ hours} ), which equals approximately 329.65 km/h. Thus, if you travel 7564 km in 23 hours, your speed is about 329.65 km/h.
15.3333
The answere would be 15.333
3 hours 23 minutes.
To convert miles to hours, you need to know the speed at which the distance is being covered. If you are traveling at a constant speed of 60 miles per hour, then it would take approximately 7.67 hours to cover 460 miles (460 miles / 60 miles per hour = 7.67 hours). It is important to note that this calculation assumes a constant speed without any stops or delays.
First you have to so some conversion. The speed is in miles per second, and the question asks how many hours it will take to travel the distance. So you have to convert the speed to miles per hour. Then you can divide the distance of 23, 900 miles by that number and find out how many hours it will take to travel the distance. There are 60 seconds in a minute; 60 minutes in an hour. So there are 60 x 60 = 3600 seconds in one hour. A speed of 17 miles per second equates to 17 x 3600 = 61, 200 miles per hour. Pretty fast! You can easily see that it wouldn't even take one full hour to complete the distance at that rate of speed. Now use the old familiar distance formula: Time = Distance /Rate. 23,900 mi./61,200 mph = about .39 hours.
Assuming you could maintain that speed and make no rest or fuelling stops, it would take 23 hours.
15.3333
23 hours
It takes 3 hours by plain and 23 hours by car.
About 15 hours 23 minutes at 65 mph
5 hours 23 minutes.
21 hours 45 mins 23 secs approx.
The answere would be 15.333
About 1,624 miles, travel time about 23 1/2 hours.
there is about 23 hours flight between the two cities
The flight times varies according to the speed of the flight. If the flight is flying at a faster speed then the times may change. We are providing you with standard flight timings. The flight time for the above mentioned trip is.23 hours
3 hours 23 minutes.