8z + 3 - 2z < 51 6z + 3 < 51 6z < 48 z < 6 ☺
Using the quadratic formula you get z≅4.91547594742265 or z≅-0.91547594742265
6z + 28 = 12z + 10 18 = 6z 3 = z
If 6z=17, divide both sides by 6 z=17/6
Firstly, we got:(-6z) (102)(-6) (102) (z)-612z-612z is the answer.
8z + 3 - 2z < 51 6z + 3 < 51 6z < 48 z < 6 ☺
Using the quadratic formula you get z≅4.91547594742265 or z≅-0.91547594742265
This is a difference of two sqaures. 49y2 - z2 = (7y - z)(7y + z)
6z-4z-z = 6-7-4 z = -5
The quotient of 4 and 5 is 4 divided by 5, which equals 0.8. The product of 6 and z is 6z. When the quotient of 4 and 5 (0.8) is added to the product of 6 and z (6z), the expression becomes 0.8 + 6z.
6z + 28 = 12z + 10 18 = 6z 3 = z
If 6z=17, divide both sides by 6 z=17/6
Firstly, we got:(-6z) (102)(-6) (102) (z)-612z-612z is the answer.
z equals 7
It can't be factored because its discriminant is less than zero.
6z+28=12z+10 6z-12z=10-28 addition property of equality. -6z=-18 simplification z=3 multiplication property of equality.
-6z + 2 = 3z + 4z + 28 Add 6z to both sides: 2 = 3z + 4z + 28 + 6z = 28 + 13z Subtract 28 from both sides: - 26 = 13z Divide both sides by 13: -2 = z