The largest 5-digit number divisible exactly by 99 is 99990.
99990 ----------------------------------------------------------------------------------------------- Largest 5 digit number is 99999 99999 ÷ 99 = 1010 r 9 → largest 5 digit number divisible by 99 is 99 x 1010 = 99990
A five-digit number that is divisible by both 9 and 4 must meet the criteria for divisibility by these numbers. A number is divisible by 9 if the sum of its digits is divisible by 9, and it is divisible by 4 if the last two digits form a number that is divisible by 4. The smallest five-digit number is 10,000, and the largest is 99,999; thus, any five-digit number that meets these criteria can be calculated by finding the least common multiple of 9 and 4, which is 36, and checking multiples of 36 within that range. For example, 10,008 is a five-digit number divisible by both 9 and 4.
98765
99,997
the largest five digit number that can be formed using the digits 7 and 9 is 97,000
99990 ----------------------------------------------------------------------------------------------- Largest 5 digit number is 99999 99999 ÷ 99 = 1010 r 9 → largest 5 digit number divisible by 99 is 99 x 1010 = 99990
A five-digit number that is divisible by both 9 and 4 must meet the criteria for divisibility by these numbers. A number is divisible by 9 if the sum of its digits is divisible by 9, and it is divisible by 4 if the last two digits form a number that is divisible by 4. The smallest five-digit number is 10,000, and the largest is 99,999; thus, any five-digit number that meets these criteria can be calculated by finding the least common multiple of 9 and 4, which is 36, and checking multiples of 36 within that range. For example, 10,008 is a five-digit number divisible by both 9 and 4.
98765
123456
99,997
the largest five digit number that can be formed using the digits 7 and 9 is 97,000
97632 is the largest number containing these digits. To make the largest number simply order the numbers in descending order. As it happens this results in an even number so nothing further is necessary.
To be divisible by 15, it must also be divisible by 3 and by 5. To be divisible by 3, the sum of the digits must be divisible by 3; to be divisible by 5, the number must end with a zero or a five. Considering all these criteria, I guess that number would be 1110.
I suggest you try getting different multiples of 41,000, until you find one that has five digits.
1
4,555,558
The only number that ONLY has two and five as factors is 10, which has two digits, so there are no numbers that are three digits long and ONLY have two and five for factors. However, if you are asking what the largest three digit number that has two and five for factors, it would be the largest three digit number with ten as a factor, as ten the the LCM of two and five, and that would be 390.