Any line that can be expressed in the form:
y=-x+C, where C is a constant
For example,
y=-x+1
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First calculate the slope of the line itself:18y = 3x + 4y = (1/6)x + (4/18)This line is in slope-intercept form; the slope in this case is 1/6.For the slope of the perpendicular line, take the negative reciprocal, -1 / (1/6), which is equal to -6.
The slope of the perpendicular to a line has a slope which is the negative reciprocal of the original line's slope.The negative reciprocal of x is -1/xSo in this case, where the slope is -2 the perpendicular line has the slope -1/(-2) or simply 1/2
NoIf the slope of a given line is x, than the slope of the line perpendicular to the first line is 1/-x. So if the first slope is negative, the second will be positive, and vice versa.
Perpendicular lines have a negative reciprocal slope. Slope of y=2x+5 is 2/1 negative reciprocal is (-1/2)
Slope of perpendicular line is the negative reciprocal. So it is -1/4