3, 9, 15
They are the multiples of 6. Since there are infinitely many of them I will not even attempt to list all of them.
No. Such a list would be infinitely long.
lcm(2, 7) = 14 → first 3 common multiples are: 14, 28, 42; lcm(2, 8) = 8 → first 3 common multiples are: 8, 16, 24; lcm(7, 8) = 56 → first 3 common multiples are: 56, 112, 168; lcm(2, 7, 8) = 56 → first 3 common multiples are: 56, 112, 168.
Start counting from 2. For each number, if it has factors besides 1 and itself, then skip it; but if it doesn't have, then write it down. When you reach 10,000, you'll have the list, and you can count them. Here's another way to do it, which is probably easier: -- Write down all the numbers from 2 to 10,000. -- Start with 2. Cross all multiples of 2 off the list. -- Then go to 3. Cross all multiples of 3 off the list. -- 4 is gone ... it was a multiple of 2 ... so go on to 5. Cross all multiples of 5 off the list. -- 6 is gone ... it was a multiple of 2 and also of 3 ... so go on to 7. Cross all multiples of 7 off the list. -- 8, 9, and 10 are gone. Go on to 11. Cross all multiples of 11 off the list. -- Keep going like this, until you reach 5,000 . You'll have the list, and you can count them.
9, 18, 27.
There are infinitely many of them and so it is not possible to list them all.
6 and 12 are multiples of 2 & 3
The first 3 multiples of 6 are: 6, 12, and 18.
LCM = 30
hmm, 3,6,9,12,15 maybe
2/3 does.
Multiples of 1- 1, 2 3, 4 ,5, 6, 7, 8, 9, 10-- Like counting Multiples of 2- 2,4,6,8,10,12, ect. Multiples of 3- 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54, Multiples of 4- Multiples of 5- Multiples of 6
The first ten multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, and 30.
If the numbers are multiples of 2, 3, and 5, they are multiples of 2 x 3 x 5 = 30. Here are some multiples of 30: 30, 60, 90, 120, 150, 180, 210, 240, 270, 300, ...
Any and all multiples of 60.
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.