1 x 38, 2 x 19.
38 x 43 = 1634 which in Roman numerals is MDCXXXIIII Multiplying XXXXIII (43) by XXXVIII (38) in Roman numerals: XXXXIII*XXXVIII = XXX(XXXX+III)+VIII(XXXX+III) Multiplying out the brackets = MCC+LXXXX+CCCXX+XXIIII Total sum of numerals = MDCXXXIIII (1634) By separating the numerals into tens and units makes multiplication a lot easier. In a way this is what we do today when tackling long multiplication.
6x2x2
How about: 8*9 = 72
1 x 76, 2 x 38, 4 x 19.
The number 39 can be expressed as a multiplication problem using the factors 3 and 13, since (3 \times 13 = 39). Additionally, it can also be represented as (1 \times 39) or (39 \times 1). These factors demonstrate the different ways to compose the number 39 through multiplication.
1 x 38, 2 x 19.
The number 38 can be obtained through multiplication by various combinations of factors. For example, 2 multiplied by 19 equals 38, as does 1 multiplied by 38. In mathematical terms, 38 is a composite number that can be expressed as the product of its prime factors, which are 2 and 19.
As a product of its prime factors: 2*19 = 38
38 is an even number so it is divisible by 2. 38 = 2*19 19 is a prime so there are no further factors.
With whole posieive numbers, there are two. 1 x 38 and 2 x 19.
38 x 43 = 1634 which in Roman numerals is MDCXXXIIII Multiplying XXXXIII (43) by XXXVIII (38) in Roman numerals: XXXXIII*XXXVIII = XXX(XXXX+III)+VIII(XXXX+III) Multiplying out the brackets = MCC+LXXXX+CCCXX+XXIIII Total sum of numerals = MDCXXXIIII (1634) By separating the numerals into tens and units makes multiplication a lot easier. In a way this is what we do today when tackling long multiplication.
6x2x2
37 x 2
How about: 8*9 = 72
1 x 76, 2 x 38, 4 x 19.
30+38
The number 39 can be expressed as a multiplication problem using the factors 3 and 13, since (3 \times 13 = 39). Additionally, it can also be represented as (1 \times 39) or (39 \times 1). These factors demonstrate the different ways to compose the number 39 through multiplication.