well it depends on how you want it. If you want it as, like having 4 quarters and counting one way for four quarters then counting another as having the same 4 quarters but in different order (if you understood any of that) there is 293 possibilities. but if you want it the other way, We can use either 0, 1, 2, 3, or 4 quarters. If we use 0 quarters, we can use from 0 up to 10 dimes, and the rest, if any, in nickels. That accounts for 11 ways. If we use 1 quarter, we can use from 0 up to 7 dimes, and the rest in nickels. That accounts for 8 ways. If we use 2 quarters, we can use from 0 up to 5 dimes, and the rest, if any, in nickels. That accounts for 6 ways. If we use 3 quarters, we can use from 0 up to 2 dimes, and the rest in nickels. That accounts for 3 ways. If we use 4 quarters, that's the whole dollar, so that accounts for 1 way. So the total number of ways = 11+8+6+3+1 = 29 You weren't asked to list them, but here is the list of all 29 ways: 1. 0 quarters, 0 dimes, and 20 nickels. 2. 0 quarters, 1 dime, and 18 nickels. 3. 0 quarters, 2 dimes, and 16 nickels. 4. 0 quarters, 3 dimes, and 14 nickels. 5. 0 quarters, 4 dimes, and 12 nickels. 6. 0 quarters, 5 dimes, and 10 nickels. 7. 0 quarters, 6 dimes, and 8 nickels. 8. 0 quarters, 7 dimes, and 6 nickels. 9. 0 quarters, 8 dimes, and 4 nickels. 10. 0 quarters, 9 dimes, and 2 nickels. 11. 0 quarters, 10 dimes, and 0 nickels. 12. 1 quarter, 0 dimes, and 15 nickels. 13. 1 quarter, 1 dime, and 13 nickels. 14. 1 quarter, 2 dimes, and 11 nickels. 15. 1 quarter, 3 dimes, and 9 nickels. 16. 1 quarter, 4 dimes, and 7 nickels. 17. 1 quarter, 5 dimes, and 5 nickels. 18. 1 quarter, 6 dimes, and 3 nickels. 19. 1 quarter, 7 dimes, and 1 nickel. 20. 2 quarters, 0 dimes, and 10 nickels. 21. 2 quarters, 1 dime, and 8 nickels. 22. 2 quarters, 2 dimes, and 6 nickels. 23. 2 quarters, 3 dimes, and 4 nickels. 24. 2 quarters, 4 dimes, and 2 nickels. 25. 2 quarters, 5 dimes, and 0 nickels. 26. 3 quarters, 0 dimes, and 5 nickels. 27. 3 quarters, 1 dime, and 3 nickels. 28. 3 quarters, 2 dimes, and 1 nickel. 29. 4 quarters, 0 dimes, and 0 nickels. Hope this helped!
None. If you "get 65 cents using only dimes nickels and quarters" you are not using any pennies!
There are 2 solutions (if you include the non-use of quarters): 1 Quarter, 2 Dimes, 2 Nickels, 45 Pennies No Quarters, 2 Dimes, 8 Nickels, 40 Pennies
You can use 1 quarter, 2 nickels, 2 dimes and 45 pennies OR 40 pennies, 8 nickels and 2 dimes
You would use 6 - one dollar bills, 9 dimes, and 5 nickles. You could also vary the dimes and nickles.
you separate a mixture of nickels and dimes by their weight
well it depends on how you want it. If you want it as, like having 4 quarters and counting one way for four quarters then counting another as having the same 4 quarters but in different order (if you understood any of that) there is 293 possibilities. but if you want it the other way, We can use either 0, 1, 2, 3, or 4 quarters. If we use 0 quarters, we can use from 0 up to 10 dimes, and the rest, if any, in nickels. That accounts for 11 ways. If we use 1 quarter, we can use from 0 up to 7 dimes, and the rest in nickels. That accounts for 8 ways. If we use 2 quarters, we can use from 0 up to 5 dimes, and the rest, if any, in nickels. That accounts for 6 ways. If we use 3 quarters, we can use from 0 up to 2 dimes, and the rest in nickels. That accounts for 3 ways. If we use 4 quarters, that's the whole dollar, so that accounts for 1 way. So the total number of ways = 11+8+6+3+1 = 29 You weren't asked to list them, but here is the list of all 29 ways: 1. 0 quarters, 0 dimes, and 20 nickels. 2. 0 quarters, 1 dime, and 18 nickels. 3. 0 quarters, 2 dimes, and 16 nickels. 4. 0 quarters, 3 dimes, and 14 nickels. 5. 0 quarters, 4 dimes, and 12 nickels. 6. 0 quarters, 5 dimes, and 10 nickels. 7. 0 quarters, 6 dimes, and 8 nickels. 8. 0 quarters, 7 dimes, and 6 nickels. 9. 0 quarters, 8 dimes, and 4 nickels. 10. 0 quarters, 9 dimes, and 2 nickels. 11. 0 quarters, 10 dimes, and 0 nickels. 12. 1 quarter, 0 dimes, and 15 nickels. 13. 1 quarter, 1 dime, and 13 nickels. 14. 1 quarter, 2 dimes, and 11 nickels. 15. 1 quarter, 3 dimes, and 9 nickels. 16. 1 quarter, 4 dimes, and 7 nickels. 17. 1 quarter, 5 dimes, and 5 nickels. 18. 1 quarter, 6 dimes, and 3 nickels. 19. 1 quarter, 7 dimes, and 1 nickel. 20. 2 quarters, 0 dimes, and 10 nickels. 21. 2 quarters, 1 dime, and 8 nickels. 22. 2 quarters, 2 dimes, and 6 nickels. 23. 2 quarters, 3 dimes, and 4 nickels. 24. 2 quarters, 4 dimes, and 2 nickels. 25. 2 quarters, 5 dimes, and 0 nickels. 26. 3 quarters, 0 dimes, and 5 nickels. 27. 3 quarters, 1 dime, and 3 nickels. 28. 3 quarters, 2 dimes, and 1 nickel. 29. 4 quarters, 0 dimes, and 0 nickels. Hope this helped!
None. If you "get 65 cents using only dimes nickels and quarters" you are not using any pennies!
In the US, we use pennies, nickels, dimes and quarters.
There are 2 solutions (if you include the non-use of quarters): 1 Quarter, 2 Dimes, 2 Nickels, 45 Pennies No Quarters, 2 Dimes, 8 Nickels, 40 Pennies
You can use 1 quarter, 2 nickels, 2 dimes and 45 pennies OR 40 pennies, 8 nickels and 2 dimes
You would use 6 - one dollar bills, 9 dimes, and 5 nickles. You could also vary the dimes and nickles.
You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.You could (a) use trial and error; (b) write two equations; or (c) call the number of nickels "n", and the number of dimes "10-n" (since there are 10 coins in total). I will use the latter approach.Number of nickels: nNumber of dimes: 10-nFor the main equation, multiply the number of coins by the value of each coin:value of nickels + value of dimes = 805n + 10(10-n) = 80Now solve the equation:5n + 100 - 10n = 80-5n = -205n = 20n = 4So, you have 4 nickels, and 6 dimes.
She can pay for the books by using a combination of dollars, nickels, and dimes based on the total amount owed. For example, she may use dollars for the larger amounts, nickels for multiples of 5 cents, and dimes for multiples of 10 cents to reach the total cost.
Three dimes, four nickels, five pennies
10 nickels, 3 dimes and 20 pennies.
Well, isn't that just a happy little question! If you have a quarter (worth 25 cents) and can't use pennies, you could make 0.65 using a quarter and a dime (10 cents), or three quarters. So, there are two combinations in this scenario - each one a unique little masterpiece!