Q: What minimum length of time is used to make normal for an area?

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You can convert units of length to units of length, and units of area to units of area. But it doesn't make sense to convert between units of length and units of area.

I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.

Surface area of the pipe: diameter*pi*length but make sure that the diameter and length are both in meters or inches.

Take its length and multiply by its width. For example:- Length-30cm,Width-19cm Area=length x width =30x19(cm) =570 units2. Answer=The area of the rectangle is 570 units2. Note: Make sure to use the same units for length and width. The result is measured in units².

It doesn't make sense to convert that. In general, you can only convert between units that measure the same thing - length to length, area to area, mass to mass, etc.

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There is no 'normal' length but if you are making them make them about 5-10cm in diameter

Just tweak it and make sure both maximum length and minimum length are the same.

Minimum length of splice is determined by local building codes, but a good rule of thumb is to make the splice length at least 20 times the bar diameter, but always at least 18" minimum.

Any length of time is a 'normal' time.

You can convert units of length to units of length, and units of area to units of area. But it doesn't make sense to convert between units of length and units of area.

I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.

Using the Scrabble dictionary, with a minimum word length of two letters, you can get 189 words. With a minimum word length of six letters, you get 91:acapniaacapniasacariasisacaridacaridanacaridansacaridsacidityacinaracrasiaacrasiasacrasinacrasinsacridityactiniaactiniasactinsadaptsadipicadscriptadscriptsairsickanisicantacidantacidsantiairantiarantiarsanticaranticityantickanticksanticsantipartyantipastiantipiracyantipyicantipyicsantiracistantiracistsantiskidantistickantitypicapiarianapiariansapiaristapiaristsapiaryarcadiaarcadianarcadiansarcadiasarcanaaridityaristaaristasarnicaarnicasartisanartisansartistartisticartistsasanasascaridascaridsascarisascidiaascidianascidiansasdicsaskantaspicsaspidistraaspirantaspirantsaspirataaspirinaspirinsastasiaastaticastrayastrictastrictsattackattacksattainattainsattarsatticsatypic

3,416 if the minimum word length is 2. 1,857 if the minimum word length is 6. 10 if the minimum word length is 12 1 calisthenics 2 catholicness 3 enthusiastic 4 histoclastic 5 schistocelia 6 sectionalist 7 technicalist 8 technocausis 9 unscholastic 10 unsocialistic

cm is not a unit of area, it is a unit of length. If you mean cm2, choose any measure (in cm) for the length, then divide 25 by that length to obtain the corresponding width.

Surface area of the pipe: diameter*pi*length but make sure that the diameter and length are both in meters or inches.

Construct it from either plywood or chipboard. It should be at least as long as the length the snake will be as an adult - and a minimum of half the length of the adult snake front to back.

The normal size for origami paper is 6in x in.