NOT CALCULUS.
Use long division. 2x2 + x - 1(4x^4)
2x^2 goes into 4x^4 2x^2 times. The remainder will then be (2x^2*(x-1)). This result(2x^3 - 2x^2) is what need to be subtracted from 4x^4 to make it exactly divisible
It is the 4th power.
No, it would be divisible by ten.
When a negative number is raised to an even power the result is a positive number
The result is 137,858,491,849
72 = 49 49/7 = 7 -----------so, not prime as the factors of 72 are 7 * 7, but 49 is divisible by more than itself and 1; it is divisible by 7
There are infinitely many such numbers. For example, take any prime number to the 11th power and the result will have exactly twelve factors.
It is the 4th power.
The smallest is 192 but there are infinitely many such numbers. For example, take any prime number to the 13th power and the result will have exactly fourteen factors. The smallest is 192.
94
No, it would be divisible by ten.
The seperation of power is exactly as it says. People separate the power.
7
A factor is a number or algebraic expression by which another is exactly divisible. A multiple is a number that can be divided by another number without a remainder. A multiple factor is an oxymoron.
No. It is divisible by many multiples of 10 to some power, at the very least.
The multiplication rule of thumb always states that a negative number times a negative number results in a positive number. Since an even number is always divisible by two, any value raised to an even integer power will result in a positive number. However, a basic proof is presented as follows: (-A) * (-A) = A^2 ((-A) * (-A)) ^ 2 = ((-A * -A) * (-A * -A)) = A^2 * A^2 = A ^ 4 ...
When a negative number is raised to an even power the result is a positive number
3+2+3²-1 = 5+8-1=12