The rule is {x : x = 2*n where n is any integer.}
rule = regulation
Each number is -4 times the previous one. That means that you can write a recursive rule as: f(1) = -3 f(n) = -4 * f(n-1) The explicit rule involves powers of -4; you can write it as: f(n) = -3 * (-4)^(n-1)
Sn = n^2
295 the rule is: f(n+1) = 2f(n) - n
The rule is t(n) = 5 + 2*n, where n = 1, 2, 3, ...
The rule is {x : x = 2*n where n is any integer.}
Since a yard is 3 feet, the rule is to multiply n by 3.
Any number can be the missing number.If you want:1: then try the rule: U(n) = (35*n^3 - 245*n^2 + 466*n - 136)/22: then try the rule U(n) = 17n^3 - 119*n^2 + 226*n - 643: then try the rule: U(n) = (33*n^3 - 231*n^2 + 438*n - 120)/24: then try the rule U(n) = 16n^3 - 112*n^2 + 212*n - 56and so on.Having said that, the simplest linear rule is U(n) = 72 - 12n, which gives 36 as the missing number.
n2+n
rule = regulation
Sn = n*(n+1)
Each number is -4 times the previous one. That means that you can write a recursive rule as: f(1) = -3 f(n) = -4 * f(n-1) The explicit rule involves powers of -4; you can write it as: f(n) = -3 * (-4)^(n-1)
Cramer's rule is applied to obtain the solution when a system of n linear equations in n variables has a unique solution.
Each number is -4 times the previous one. That means that you can write a recursive rule as: f(1) = -3 f(n) = -4 * f(n-1) The explicit rule involves powers of -4; you can write it as: f(n) = -3 * (-4)^(n-1)
Sn = n^2
T(n) = (-n)3