Two times 35 is 70. 63 isn't large enough for 35 to go in twice.
HCF(63, 35) = 7
315
Oh, dude, let me calculate that for you... So, 35 can go into 63 once, with a remainder of 28. It's like when you're trying to fit into those skinny jeans after Thanksgiving dinner - you might squeeze in once, but there's always a little extra hanging out.
63 goes into 917 14 times with remainder 35.
315
Any multiple of 315
315, 630, 945, 1260 +315 . . .
It is 7 number. 35/7= 5 and 63/7= 9
Two times 35 is 70. 63 isn't large enough for 35 to go in twice.
HCF(63, 35) = 7
Oh, dude, let me calculate that for you... So, 35 can go into 63 once, with a remainder of 28. It's like when you're trying to fit into those skinny jeans after Thanksgiving dinner - you might squeeze in once, but there's always a little extra hanging out.
7! sevenxfive=35, sevenxeight=56, and sevenxnine=63 ;)
1 and 7.
315
63 goes into 917 14 times with remainder 35.
The HCF of both numbers is 7