Q: What number can be divisible by 312?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

Because their quotient is a whole number.

You can easIly figure this out by using the fact that all even numbers are Divisible by 2. Because 312 is even it to Is also divisible by 2. Because 312 can be divided by mOre than itself and one, which is what a prime number is, it is composiTe.

510

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.

312 is divisible by 2 b/c the 2 at the end of 312 is an even number312 is divisible by 3 b/c 3 + 1 + 2 = 6 which is divisible by 3312 is divisible by 4 b/c 12 is divisible by 4312 is not divisible by 5 b/c the one's place isn't 0 or 5312 is divisible by 6 b/c 312 is divisible by 2 and 3312 is not divisible by 7 b/c 2*7=14, 31-14=17 which is not divisible by 7312 is divisible by 8 b/c 312/8=39 (Explanation: A way to find out how 8 is divisible its that its first three digits [the ones, tens, and hundreds place] have to be divisible by 8)312 is not divisible by 9 b/c 3 + 1 + 2 = 6 which is not divisible by 9312 is not divisible by 10 b/c the ones place is not 0

Related questions

312 is divisible by 9 but the answer is not a whole number, it is... 34.666 recurring.

624 is divisible by 312.

Because their quotient is a whole number.

You can easIly figure this out by using the fact that all even numbers are Divisible by 2. Because 312 is even it to Is also divisible by 2. Because 312 can be divided by mOre than itself and one, which is what a prime number is, it is composiTe.

A number is divisible by 4 if the last two digits form a number that is divisible by 4, e.g. 312 is divisible by 4 (because 12 is divisible by 4).

510

All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.

Finding divisibility by 3 and 9 are very easy to do. Simply add up the digits in the number and see if they are divisible by the number you are looking for. 3+1+3=7 and 7 is not divisible by 3, is 313 is not either. ◄ 3+1+2=6 and 6 is divisible by 3, so 312 is also. 312/3=104

Yes.

312 is divisible by 2 b/c the 2 at the end of 312 is an even number312 is divisible by 3 b/c 3 + 1 + 2 = 6 which is divisible by 3312 is divisible by 4 b/c 12 is divisible by 4312 is not divisible by 5 b/c the one's place isn't 0 or 5312 is divisible by 6 b/c 312 is divisible by 2 and 3312 is not divisible by 7 b/c 2*7=14, 31-14=17 which is not divisible by 7312 is divisible by 8 b/c 312/8=39 (Explanation: A way to find out how 8 is divisible its that its first three digits [the ones, tens, and hundreds place] have to be divisible by 8)312 is not divisible by 9 b/c 3 + 1 + 2 = 6 which is not divisible by 9312 is not divisible by 10 b/c the ones place is not 0

104 is divisible by 6?

Yes.