To get this answer, you will need to divide both answers by 5 first, because that is the obvious number that will go into both. 385/5= 77 420/5=84 So the new fraction is 77/84. 7 will go into both (it goes into 70, and 70 plus 14(another multiple of 7!) = 84) 77/7=11 84/7=12 385/420 in its simplest form is 11/12!
84
Itself and any of its factors
1, 2 and 4
The hcf is 21
84/33 = 2 and 18/33 Hence 33 goes into 84 two times with a remainder of 18 or 2.54 (recurring) times in decimal
Any number of the form 84*k, where k is an integer, is evenly divisible.
The number that can go into both 100 and 33 is 1. In mathematics, every number is divisible by 1. This is because division by 1 results in the original number. Therefore, 1 can evenly divide both 100 and 33 without leaving a remainder.
Find factors that can go into both numbers. The most obvious that can do this is 2. So 84/166 = 42/83 No other number can go into both 42 and 83.
1 and 2 both go into 38 and 84.
81 and 84 both go into 6804. The LCM is 2268.
33 is a composite number because 11 can go into 33 3 times and itself and 1 can go into 33. :)
well if you look... 2 goes in to both because the last digit of each number end in an even number there you go <33
The LCM of both numbers is 84
84, 168, 252, 336, 420 +84 . . .
Their LCM is 84
To get this answer, you will need to divide both answers by 5 first, because that is the obvious number that will go into both. 385/5= 77 420/5=84 So the new fraction is 77/84. 7 will go into both (it goes into 70, and 70 plus 14(another multiple of 7!) = 84) 77/7=11 84/7=12 385/420 in its simplest form is 11/12!