10 before 241 = 231
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Your question is invalid here but i am nice so i will answer it. Well I'm sorry but the english counting ways go 1,2,3,4,5,6,7,8,9,10 and so on. As you can see 9 is before 10.
241. Un = 3(n+2)/3 - 2 for n = 1 mod 3.
The number that comes after 9100 is 9101. In the base-10 number system, each digit can range from 0 to 9 before incrementing to the next place value. Therefore, when we increment the last digit of 9100 by 1, it becomes 9101.
When a smaller numeral comes before a larger numeral it is subtracted. L = 50 X = 10 I = 1 → XLIX = (-10 + 50) + ( -1 + 10) = 40 + 9 = 49