Given any number it is easy to find a rule based on a polynomial of order 7 such that the first seven numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.
The simplest solution, using a polynomial of order 6, is
Un = -0.0069n6 + 0.1708n5 - 1.6319n4 + 7.6458n3 - 18.3611n2 + 23.1833n - 10 for n = 1, 2, 3, ...
Accordingly, the next term is 11.
14
6.
what number comes next 1 -8 -16 -24 -33
Probable answer is 11 as shown below:1 + 5 = 65 + 6 = 116 + 11 = 1711 + 17 = 28
It's a pattern of odd numbers- so... nine is next, then eleven, and so on. 1-3-5-7-9-11....
13
42 as you have to add the next prime number onto the previous value.
14
6.
42 is the next number in this sequence. This number sequence is adding the next prime number to the last number. So 1 + 2 = 3. Then 3 + 3 = 6, 6 + 5 = 11, 11 + 7 = 18, 18 + 11 = 29. The next prime number after 11 is 13, so 29 + 13 = 42. The next numbers would be 59 (42+17), 78 (59+19), and 101 (78+23)
what number comes next 1 -8 -16 -24 -33
Probable answer is 11 as shown below:1 + 5 = 65 + 6 = 116 + 11 = 1711 + 17 = 28
1 1 1
-27 You subtract powers of 2 everytime... 1,2,4,8,16
It's a pattern of odd numbers- so... nine is next, then eleven, and so on. 1-3-5-7-9-11....
The number 0 and the next is 2.
13 or 100, what are you looking for? 100 Liz is right