When the term # = t, and the term = m, the equasion is 2(x2) = n.
Therefore, to solve this equation, solve: 2(62).
62 = 36
2(36) = 72
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32
65 (each jump is 3, 6, 9, 12, 15, 18, etc)
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Using the simplest polynomial of order 4, Un = (-23n4 + 266n3 - 1033n2 + 1630n - 32)/24, for n = 1, 2, 3, ... the next number will be 22.
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