Given any number, it iis possible to find a polynomial of degree 5 that will fit the above points and the additional point. Consequently, a rule can be found that can justify any number as the "next".
The only polynomial of order 4 is
Un = (-3n4 + 40n3 - 185n2 + 336n - 176)/4 for n = 1, 2, 3, ...
Accordingly, the next number is -17
311311122110
16 is the next squared number.
555 ;) :() :0 :) ;0 love u guys hope this helps
You cant solve the next term (next number) in this sequence. You need more terms, because this is either a "quadratic sequence", or a "linear and quadratic sequence", and you need more terms than this to solve a "linear and quadratic sequence" and for this particular "quadratic sequence" you would need more terms to solve nth term, which would solve what the next number is. If this is homework, check with your teacher if he wrote the wrong sum.
20
The next number is 0
The next number in the sequence is 48.
311311122110
There are infinitely many different polynomials of degree 8 that will fit all the numbers of the above sequence. Each will generate a different number as the next one in the sequence.
16 is the next squared number.
555 ;) :() :0 :) ;0 love u guys hope this helps
You cant solve the next term (next number) in this sequence. You need more terms, because this is either a "quadratic sequence", or a "linear and quadratic sequence", and you need more terms than this to solve a "linear and quadratic sequence" and for this particular "quadratic sequence" you would need more terms to solve nth term, which would solve what the next number is. If this is homework, check with your teacher if he wrote the wrong sum.
20
The next number is 4, followed by -2
1
215
This sequence is all the single digits, written in reverse alphabetical order. The first value is 0, and zero comes last alphabetically. The next value is 2, and two comes second last alphabetically, and so on. From this, it is clear that the next few numbers will be 9,4,5 and 8 (eight being the first number alphabetically) and then the sequence will end.