The only number I seem to be able to find is:
* 1 Unless one wants to use rational and Irrational Numbers.
That is a different story.
nine
117 goes into 130 once with remainder 13.
To determine how many times 9 goes into 117, you can divide 117 by 9. Doing the calculation, 117 ÷ 9 equals 13. Therefore, 9 goes into 117 a total of 13 times.
To find out how many times 15 goes into 117, you divide 117 by 15. Doing the calculation, 117 ÷ 15 equals 7.8. Therefore, 15 goes into 117 a total of 7 times, with a remainder or fraction left over.
117/0.45 = 260
nine
1, 3, 9, 13, 39, 117.
117 goes into 130 once with remainder 13.
Nothing
6 goes into 117 a total of 19 times. This can be calculated by dividing 117 by 6, which equals 19 with a remainder of 3. Therefore, 6 goes into 117 exactly 19 times.
To determine how many times 9 goes into 117, you can divide 117 by 9. Doing the calculation, 117 ÷ 9 equals 13. Therefore, 9 goes into 117 a total of 13 times.
1, 3, 9, 13, 39, 117.
An infinite number of of multiples of 117 can be divided by 117.
To find out how many times 15 goes into 117, you divide 117 by 15. Doing the calculation, 117 ÷ 15 equals 7.8. Therefore, 15 goes into 117 a total of 7 times, with a remainder or fraction left over.
13
117/0.45 = 260
117 / 0.78 = 150