well, no number goes int 5 or 7 that can also go into 8 or 4.
1 goes into 7 and 5 and 8 and 9 and 6
The number 7 goes into both 56 and 119 (56/7 = 8, 56/7 = 17).
Only the number 1
0 is the missing number.
To determine what number goes into 5, 7, and 8, we need to find the greatest common factor (GCF) of these three numbers. The GCF is the largest number that divides evenly into all three numbers. In this case, the GCF of 5, 7, and 8 is 1, as there are no common factors other than 1 among these numbers. Therefore, the number that goes into 5, 7, and 8 is 1.
1 goes into 7 and 5 and 8 and 9 and 6
well, no number goes int 5 or 7 that can also go into 8 or 4.
To find out how many times one number goes into a second number divide the second number by the first number; In this case 56 ÷ 8 = 7.
i may be wrong, but, from the way i see it, it appears that every other number increases by one. so, let's start by viewing the pattern. it goes 5, 7, 6, 8, 7.now if you will notice each number counts up one if you start from the first number and skip one in between. it goes 5 6 7. or to see it within the pattern, 5 7 6 8 7 ? (i will substitute the unknown number for x.)the same pattern happens with the numbers starting from the second one and skipping one in between. it counts up one like 7 8 x(unknown #). also, to see this in the patter, 5 7 6 8 7 x.so from there all you should have to do is follow theh pattern given. it would be eight and progress like this: 5 76 8 7 (9 8 10). (the first # in parenthises should be the one you are looking for.)
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standing in front of the vehicle starting on the driver side it goes 5 6 7 8
The number 7 goes into both 56 and 119 (56/7 = 8, 56/7 = 17).
If you are on a 10 hole harmonica it goes like this: 6 7 8 7 8 -8 7 -6 6 6 7 8 7 8 -8 9 8 9 8 7 6 -6 7 -6 6 6 7 8 7 8 -8 7 If I were you, I'd play it on the key of G because if it's on the key of C it gets hard to breathe. But you can play it in any key; that's the beauty of it.
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