let x be the number, then: (x + 1) × 2 + 5 = x + 1 → 2x + 2 + 5 = x + 1 → 2x + 7 = x + 1 → 2x - x = 1 - 7 → x = -6 The number is -6. Checking: -6 +1 = -5; 5 × 2 = -10; -10 + 5 = -5 which is the same as -6 + 1 = -5.
23 + 2X = 5 2X = -18 X = -9
2 -> 9 = +79 -> 5 = -45 ->13 = +813 -> 10 = -310 -> 19 = +919 -> 17 = -2As you can see, every other time, the number is increased. It was originally increased by 7, then 8, then 9. So, the next number should be increased by 10 = 27
Let x = the numbernumber increased by 10 = x + 10
It will be 22348.
let x be the number, then: (x + 1) × 2 + 5 = x + 1 → 2x + 2 + 5 = x + 1 → 2x + 7 = x + 1 → 2x - x = 1 - 7 → x = -6 The number is -6. Checking: -6 +1 = -5; 5 × 2 = -10; -10 + 5 = -5 which is the same as -6 + 1 = -5.
23 + 2X = 5 2X = -18 X = -9
3x+30let x = "a number"(x+10) = "a number increased by 10"3(x+10) = "3 times a number increased by 10"Expand: 3x+30
x+8+x/5 = 20 x = 10
2 -> 9 = +79 -> 5 = -45 ->13 = +813 -> 10 = -310 -> 19 = +919 -> 17 = -2As you can see, every other time, the number is increased. It was originally increased by 7, then 8, then 9. So, the next number should be increased by 10 = 27
Let x = the numbernumber increased by 10 = x + 10
Five more than (5+)four times (4*)a number (x)is (=)that number (x)increased by 35. (+35)5 + 4x = x + 35Subtract an x from both sides5 + 3x = 35Subtract 5 from both sides3x = 30Divide by 3x = 10◄check back into original equation.5+4(10) = (10)+355+40 = 45■
It will be 22348.
-5
n+5
5p+10
X-5^2