You can see quickly that the number 57 is divisible by 3: 3 * 20 = 60 so if we remove one of those 3's then 3 * 19 = 57 so it is divisible by at least 3 and 19 (as well as itself and 1) Because it is divisible by numbers other than itself and one, 57 cannot be prime. You can also check to see if a number is divisible by 3 by adding its digits and checking to see if that number is divisible by 3: 5+7 = 12 ; and 12 is divisible by 3, so 57 is as well.
57 divided by 3 is 19. (Any number in which all the digits add up to equal a number divisible by 3 is divisible by 3. 5+7=12 which is divisible by 3.) And since 57 is divisible by more numbers than just 1 and itself it is a composite number.
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
because it is divisible by 3!
Any of its multiples! Simply calculate any of the following: 57 x 0 57 x 1 57 x 2 57 x 3 57 x (-1) 57 x (-2) etc., and you get a number that is a multiple of 57, and therefore, divisible by 57.
You can see quickly that the number 57 is divisible by 3: 3 * 20 = 60 so if we remove one of those 3's then 3 * 19 = 57 so it is divisible by at least 3 and 19 (as well as itself and 1) Because it is divisible by numbers other than itself and one, 57 cannot be prime. You can also check to see if a number is divisible by 3 by adding its digits and checking to see if that number is divisible by 3: 5+7 = 12 ; and 12 is divisible by 3, so 57 is as well.
57 divided by 3 is 19. (Any number in which all the digits add up to equal a number divisible by 3 is divisible by 3. 5+7=12 which is divisible by 3.) And since 57 is divisible by more numbers than just 1 and itself it is a composite number.
57 divided by 3 is 19. (Any number in which all the digits add up to equal a number divisible by 3 is divisible by 3. 5+7=12 which is divisible by 3.) And since 57 is divisible by more numbers than just 1 and itself it is a composite number.
57 is a prime number meaning it is only divisible by itself and the number 1. no so does 3 (FL0W Answr ) Thats not true 19 goes into 57 3 times
composite. 57 divided by 3 is 19. (Any number in which all the digits add up to equal a number divisible by 3 is divisible by 3. 5+7=12 which is divisible by 3.) And since 57 is divisible by more numbers than just 1 and itself it is a composite number.57 is a composite number since it can be divided by 3.57/3 = 19Composite.
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
No, it is divisible by 3 & 19
because it is divisible by 3!
Any of its multiples! Simply calculate any of the following: 57 x 0 57 x 1 57 x 2 57 x 3 57 x (-1) 57 x (-2) etc., and you get a number that is a multiple of 57, and therefore, divisible by 57.
To be sure, prime numbers are a number which cannot be divisible by every number except for itself and one. Take 5 for an example. There is no possible number which is divisible by itself except for itself and one. So, 5 is a prime number.2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 are all prime numbers to 100. Let's refresh our mind. Now, 57 has factors of 1, 3, 19, and 57. Let's remove the 57 and 1. Now, 3 and 19 are all the factors of 57.
The number is 57.
It is 57.