Yes, it's true. 3 is one of the factors of 6, so any number that has six as a factor also has 3 as a factor.
First you add up all of the digit's, and then divide. If 6 fits in it, then 3 also fits in it, but not 9. (For ex. Is 6 a factor of 674. 6+7+4=17, 17/6=2.8. so no, 6 is not a factor of 674) If your number is even and divisible by three, it's divisible by 6.
Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.
If a number is divisible by 2 and 3, it is divisible by 6.
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
Yes. If a number is divisible by another number, that second number is a factor of the first. 6 is divisible by 2, 2 is a factor of 6.
Well, isn't that just a happy little math problem! Let's see here... numbers that are divisible by 3 but not by 6 would be 12, 15, 18, 21, 24, 27, 33, 39, 42, 45, 48, 51, 57, 63, 69, 72, 75, 78, 81, and 87. Remember, math is just like painting - it's all about finding the right colors and shapes that fit together beautifully!
Yes, it's true. 3 is one of the factors of 6, so any number that has six as a factor also has 3 as a factor.
Oh, what a lovely question! When a number has 6 as a factor, it means it can be divided evenly by 6. If a number can be divided by 6, it must also be divisible by 3 because 6 is made up of 3 multiplied by 2. So, yes, numbers with 6 as a factor will also have 3 as a factor. Just like adding happy little trees to a painting, numbers and their factors work together in harmony.
492 is an even number so it must be divisible by 2. Its digits total a multiple of 3 so it must be divisible by 3. Any even number that is divisible by 3 is divisible by 6. Of course, you can always divide 492 by 6. If it comes out even, it's a factor. (It does.)
First you add up all of the digit's, and then divide. If 6 fits in it, then 3 also fits in it, but not 9. (For ex. Is 6 a factor of 674. 6+7+4=17, 17/6=2.8. so no, 6 is not a factor of 674) If your number is even and divisible by three, it's divisible by 6.
Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.
234 is even and divisible by three. It has to be divisible by 6.
No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
A number that is divisible by 6 but not by 3 must be a multiple of 6 that is not a multiple of 3. Since 6 is a multiple of 3 (6 = 2 * 3), any multiple of 6 will also be a multiple of 3. Therefore, there is no number that is divisible by 6 but not by 3.
138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)