If a number, when divided by 6, is more than 5, then the number must be greater than 30 and so cannot be between 29 and 30.
20 and 30 are rectangular numbers (4 * 5 and 5 * 6). There are none in between them.
29 - 23 = 6
It's a multiple of 5, a multiple of 6 (since it's between twin primes), and less than 50. The only possibility is 30. To check: The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30
25
36 is a square number between 30 & 40. 36 is 6 squared.
If a number, when divided by 6, is more than 5, then the number must be greater than 30 and so cannot be between 29 and 30.
The two perfect numbers between 1 and 30 are: 6, 28
20 and 30 are rectangular numbers (4 * 5 and 5 * 6). There are none in between them.
29 - 23 = 6
It is 28 I did that at school in year 6
The differences between a number and the number two on is alternating between 6 and 3. In this case, the next number will be 24 + 6 = 30.
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
Every number divisible by 6 is a multiple of two. So: 6, 12, 18, 24, 30
6% of 30= 6% * 30= 0.06 * 30= 1.8
10, 15, 20, 25 and 30
It is: 1/5 of 30 is 6