If a number, when divided by 6, is more than 5, then the number must be greater than 30 and so cannot be between 29 and 30.
29 - 23 = 6
20 and 30 are rectangular numbers (4 * 5 and 5 * 6). There are none in between them.
It's a multiple of 5, a multiple of 6 (since it's between twin primes), and less than 50. The only possibility is 30. To check: The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30
25
36 is a square number between 30 & 40. 36 is 6 squared.
If a number, when divided by 6, is more than 5, then the number must be greater than 30 and so cannot be between 29 and 30.
The two perfect numbers between 1 and 30 are: 6, 28
29 - 23 = 6
20 and 30 are rectangular numbers (4 * 5 and 5 * 6). There are none in between them.
It is 28 I did that at school in year 6
The differences between a number and the number two on is alternating between 6 and 3. In this case, the next number will be 24 + 6 = 30.
To find a number between 80 and 100 that is divisible by both 5 and 6, we need to find the least common multiple (LCM) of 5 and 6, which is 30. We then look for a multiple of 30 between 80 and 100, which is 90. Therefore, the number 90 between 80 and 100 is divisible by both 5 and 6.
Every number divisible by 6 is a multiple of two. So: 6, 12, 18, 24, 30
6% of 30= 6% * 30= 0.06 * 30= 1.8
10, 15, 20, 25 and 30
It is: 1/5 of 30 is 6