Here's one way to find a number that is divisible by 3:
If the digits of the number add up to 3, 6, or 9, then it is divisible by 3.
For example, 321 is divisible by 3 because 3+2+1=6. (If the sum of the digits isn't one digit, just add those digits as well until you get to one digit (for example, 999--> 9+9+9=27, 2+7=9))
A number that is between 200 and 250 divisble by 3 not 2 is 249
Yes and it is 292
3 and 5 are divisable by 195
yes for a number to be divisble by 3 you have to add the numbers together and see if you can divide it by 3 evenly 1+5+3= 9 9 can be divided by 3 evenly so that makes the number, 153 divisble by 3
105
A number that is between 200 and 250 divisble by 3 not 2 is 249
Yes and it is 292
30
3 and 5 are divisable by 195
yes for a number to be divisble by 3 you have to add the numbers together and see if you can divide it by 3 evenly 1+5+3= 9 9 can be divided by 3 evenly so that makes the number, 153 divisble by 3
456
105
-1
888 because 8 is divisble by 2 and 8+8+8 is 24 24 is divisible by 3 then it is divisible by 2 and 3 then it is divisble by 6....
No. For example, 9 is divisible by 3 and 9, but not 6. Even numbers that are divisble by 3 and 9 are also divisble by 6.
All numbers in the 3 times table. For example; 3, 6, 9, 12 . . .
Any number that is divisible by both 2 and 3 is divisible by 6.