List the prime factors of each of these numbers, then multiply all the prime factors. The prime factor 2 has to be included twice, since it appears twice in the number 4. Other prime factors, in this case, only have to be included once.
Prime numbers are only divisible by 1 and themselves. So, a prime number cannot be divisible by 10. The only prime number that is divisible by 2 is 2 itself; all other numbers divisible by 2 are not prime numbers.
1
Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.
No.A number a is divisible by another number b, if and only if the fraction a/b is equivalent to a whole number. And as you know, 1/2 = 0.5, which is not a whole number, hence is 1 not divisible by 2.The only number 1 is divisible by, is 1 itself. All numbers are divisible by 1.
Yes, the number 1720 is divisible by 3 because the sum of its digits (1 + 7 + 2 + 0) is equal to 10, which is divisible by 3.
3 <><><> 3 is only divisible by 1 and itself. whereas 4 and 10 are divisible by other numbers. 4 is divisible by 1,2,4. 10 is divisible by 1,2,5,10 <><><> A prime number is a number that is evenly divisible only by itself and one. Therefore, 3 is the prime number. 4 is divisible by 1, 2, and 4. 10 is divisible by 1, 2, 5, and 10. Three cannot be divided evenly by any other whole number. So, 3 is the prime number.
Nope, 10 is divisible by 5, 2, and 1. You are looking for the number 12. 12 is divisible by 6.
90.
Because 10 is divisible by both 2 and 5
87 is divisible by 1, 3, 29, and 87. 100 is divisible by 1, 2, 4, 5, 10, 20, 25, 50, and 100, therefore the only number divisible by 87 and 100 is 1.
10 is divisible by 1, 2, 5 & 10
There are no numbers that satisfy this. If a number is divisible by both 2 and 5, then it must also be divisible by 10.
It's clearly divisible by 10 and 2 for starters
1- Any number is divisible by 1. 2- Any even number is divisible by 2. 3- If its digits add up to a number divisible by 3, the whole number is divisible by 3. 4- If the last two digits are divisible by 4, the whole number is divisible by 4. 5- If it ends in 5 or 0, the whole number is divisible by 5. 6- If it's even and also divisible by 3, the whole number is divisible by 6. 7- There is no rule for 7. 8- If the last three digits are divisible by 8, the whole number is divisible by 8. 9- If its digits add up to a number divisible by 9, the whole number is divisible by 9. 10- If it ends in 0, the whole number is divisible by 10.
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.
If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10
180