The mean (average) of 250 and 500 is 375. ((250+500)/2)
750
The years between are the years from 249 BC to 1BC, and 1AD to 249AD, ie. 498 years.
500 and divide by 250 = 2
500
250 less than 500 = 500 - 250 500 - 250 = 250
The number is 250.5 because it is exactly 249.5 from either 1 or 500.
355 is exactly between the two numbers.
The mean (average) of 250 and 500 is 375. ((250+500)/2)
If you include the number 3,000, there are exactly 2,001 4-digit numbers between 500 and 3000.
The answer to this mathematical problem is 250. How I came to this conclusion is that all you do is add 100 and 400 which = 500. Then you simply divide 500 by 2 and get the quotient of 250! Then boom that's your answer!
it is 250
125.
750 It is 250 more than 500 and 250 less than 1000. To find the halfway point (the average), add the two numbers and divide by 2.
750
yes i promis
The years between are the years from 249 BC to 1BC, and 1AD to 249AD, ie. 498 years.