49
You could put 49 in between the 16 and the 100.
c) 17
22
The missing numbers are 9 & 49.The sequence is 1x1, 2x2, 3x3, 4x4, 5x5, 6x6, 7x7& 8x8.
49
256 (each number is the square of the preceding number)
You could put 49 in between the 16 and the 100.
16
c) 17
9 (between 8 and 16).
22
The missing numbers are 9 & 49.The sequence is 1x1, 2x2, 3x3, 4x4, 5x5, 6x6, 7x7& 8x8.
While there are not enough numbers to fully clarify the nth term of the sequence, according to the sequence so far it appears that the nth term is equal to n4. Therefore, the next number will equal 44 = 256
The solution depends on how many numbers are missing and where they were. If there is only one, If it is between 4 and -5 then -0.5 If it is between -5 and -10 then -8 If it is between -10 and -16 then -13 Of course, the answer would be different if there were more than one number missing.
Assuming the space is between the 5 and the 37, you could put 21 in there and all the numbers would be 16 apart from each other.
They are 25 and 49