A number not even would not divisible by 2.
If the digits don't add up to something divisible by 3 and it doesn't end in 5 or 0 then it meets your criteria.
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If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
Any multiple of 30.
211
Answer: 3/3x 2/5=90/15How To solve the problem: 3/3 x 2/51. Find the GCM (Greatest Common Multiple) (3)3,6,9,12,15-(5)5,10,15= 152.Multiple 3X5=15,Then Multiple the top number(3)by 5=15Combined=15/153.Multiple 5X3=15,Then Multiple the top number(2) by 3=6 Combined=6/154.Multiple the two new factors(15/15 X 6/15)5.Then you get the answer... 90/15
The number you're looking for is 4. It's an even number, and when you add 5 to it, the result is 9, which is a multiple of 3.
The smallest multiple of 2,3,4, and 5 is 60 ■
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
30 is a multiple of 2, 3 and 5.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
A multiple of a number is something you get when you multiply that number by another. For instance, 5 x 2 = 10, so 10 is a MULTIPLE of 5 and a MULTIPLE of 2. If you're trying to find a multiple of a number, say, 3, multiply that number by another. It can be any number.
Any multiple of 30.
Which number is a factor of 10 , but not a multiple of 5
90. The Least Common Multiple of 2, 3 and 5 is 30 and the multiple of 30 that is between 80 and 100 is 90.
1 and 5
30 and all its infinite number of multiples...
60