Q: What number other than 0 is it's own square root?

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No, not always since: if a number is more than 1, then its square root is smaller than the number. if a number is less than 1, then its square root is bigger than the number.

It is if the number is more than ' 1 '. If the number is less than ' 1 ', then it's smaller than its own square root.

A square root is simplified when: -The radicand has no perfect square factors other than 1 -The radicand has no fractions -There are no square roots in the denominator *Radicand: the number and/or variables underneath the square root sign

The square root of the number acts sort of like the 'multiplicative middle' of the number. When you multiple the square root by itself, you get back to original number. When you search for factors of the number (easier to see when thinking of real numbers) it's intuitive that you must have one number on either side of this 'multiplicative middle'

Since the square root of a number is the "number times itself that equals the original number," it makes sense that the larger the original number, then the larger the square root. The value of the square root of 2 will be greater than the value of the square root of 1.5.

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No, not always since: if a number is more than 1, then its square root is smaller than the number. if a number is less than 1, then its square root is bigger than the number.

Such a number is called a "perfect square".

negative 6

It is if the number is more than ' 1 '. If the number is less than ' 1 ', then it's smaller than its own square root.

A square root is simplified when: -The radicand has no perfect square factors other than 1 -The radicand has no fractions -There are no square roots in the denominator *Radicand: the number and/or variables underneath the square root sign

The square root of the number acts sort of like the 'multiplicative middle' of the number. When you multiple the square root by itself, you get back to original number. When you search for factors of the number (easier to see when thinking of real numbers) it's intuitive that you must have one number on either side of this 'multiplicative middle'

There is no three digit prime number whose square root is a prime number. Prime numbers have no factors other than 1 and themselves. Any number having a prime number as a square root is a composite number.

Since the square root of a number is the "number times itself that equals the original number," it makes sense that the larger the original number, then the larger the square root. The value of the square root of 2 will be greater than the value of the square root of 1.5.

False. Only a square number greater than 1 is always bigger than its root. For example, the root of 16 is 4, but the root of 1/16 (0.0625) is 1/4 (0.25) and the square root of 1 is 1.

when the number is greater than 1

No there is not. If you are looking for prime factors of a number and you get to the square root of that number you can stop. Yes, there is. If an integer is not itself a prime, then one of its factors will be less or equal to its square root and the "co-factor" will be greater than or equal to the square root. But both cannot be greater than the square root so, when searching for factors, you can stop when you reach the square root.

Yes, of some; the square root of any perfect square is rational - for example, the square root of 4, of 9, of 16, etc.On the other hand, if your "composite number" is not a perfect square, then its square root is irrational.