im not quite sure but i have received a similar assignment in one of my classes recently and cant figure it out either. if you now know the answer to this question could you please tell me the answer?
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A square root is not a number system. Square roots of non-negative numbers may be rational or irrational, but they all belong to the set of real numbers. The square roots of negative numbers do not. To include them, the number system needs to be extended to the complex numbers.
It is an irrational number, and therefore a real number.
No, there is no real number that satisfies the equation √(-28). The square root of a negative number is not defined in the real number system. However, if we extend our number system to include complex numbers, we can define a square root of -28 as √(-28) = 2√7i, where i is the imaginary unit.
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The square root is the number which is times by itself, to get the square number.