77040
72
Each number is multiplied by an incrementing value. 107 is multiplied by 2, 214 is multiplied by 3, 642 is multiplied by 4 and so on.
119. un = (-n4 + 15n3 - 77n2 + 225n + 192)/6
107 double difference each time 2 + 7 = 9 9 + 7 + 7 = 23 23 + 14 + 14 = 51 51 + 28 + 28 = 107
77040
77,040
If the fourth term were 2568 there is a simple answer, but with the series going up and down, I have no clue.
72
Each number is multiplied by an incrementing value. 107 is multiplied by 2, 214 is multiplied by 3, 642 is multiplied by 4 and so on.
The next number is 77040. Solution: 107 x 2 = 214x 3 = 642 x 4 = 2568 x 5 = 12840 x 6 = 77040
119. un = (-n4 + 15n3 - 77n2 + 225n + 192)/6
77040. It goes like, 107 * 2 = 214 214 * 3 = 642 642 * 4 = 2568, and so on. x * a(+1) = (a new)x Except that the word "completes" would suggest that there are no more terms. Not true!
107 98 90 83 77 __ 68 65
9-2=7, 23-9=14, 51-23=28, 107-51=56. therefore, since the next number in the sequence will be twice the previous difference, it will be 107+112 which is 219
1 and 107 (107 is a prime number).
107 double difference each time 2 + 7 = 9 9 + 7 + 7 = 23 23 + 14 + 14 = 51 51 + 28 + 28 = 107