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Best Answer
xy = 6
x + y = 8 so y = 8 - x
xy = 6 substitute y with 8 - x
x(8 - x) = 6
8x - x2 = 6 subtract 6 to both sides, then multiply each term by -1
x2 - 8x + 6 = 0 use the quadratic formula to find x
x = (8 ± √(64 - 24)/2
x = (8 ± √40)/2 write 2 as 4 into the radical
x = 8/2 ± √(40/4)
x = 4 + √10 or x = 4 - √10
Therefore, the numbers are 4 + √10 and 4 - √10.
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