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xy = 6

x + y = 8 so y = 8 - x

xy = 6 substitute y with 8 - x

x(8 - x) = 6

8x - x2 = 6 subtract 6 to both sides, then multiply each term by -1

x2 - 8x + 6 = 0 use the quadratic formula to find x

x = (8 ± √(64 - 24)/2

x = (8 ± √40)/2 write 2 as 4 into the radical

x = 8/2 ± √(40/4)

x = 4 + √10 or x = 4 - √10

Therefore, the numbers are 4 + √10 and 4 - √10.

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