They represent 710 in Roman numerals
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500 + 100 + 100 + 10 = DCCX
It is: 710 = DCCX.
D = 500 C = 100 (so CC = 200) X = 10 DCCX = 710
Just tackle the problem in the same way as you would work out a problem in long multiplication and then add up the products as follows:- C times DLXX = (LVII) => 100*570 = 57,000 XXX times DLXX = (XVII)C => 333*570 = 17,100 V times DLXX = (II)DCCCL => 5*570 = 2,850 III times DLXX = (I)DCCX => 3*570 = 1,710 (LVII)+(XVII)C+(II)DCCCL+(I)DCCX = (LXXVIII)DCLX 57,000+17,100+2,850+1,710 = 78,660 Note that numerals within brackets indicate multiplication by 1,000.
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