No, to determine if a number is divisible by nine, add up the digits. If the sum is divisible by 9, then the number is divisible by 9. So 519 -> 5 + 1 + 9 = 15, which is not a multiple of nine. This 'trick' works on divisible by 9 and also divisible by 3, so 519 is divisible by 3, since 5 + 1 + 9 = 15, which is a multiple of 3. Yes. The result is a fraction though.
Not evenly because it will have a remainder of 3
519
All numbers are divisible by 1.
Prime numbers are divisible because any numbers that are divisible are prime. If a number isn't divisible, it isn't prime. Prime numbers have to be divisible by at least one pair of numbers to be prime.
It is divisible by any of its factors which are 1, 3, 173 and 519
3, 173, 5.19, 51.9, 519
All multiples of 173 (which are infinite) including 173, 346, 519, 692, 865, 1038 . . .
No, to determine if a number is divisible by nine, add up the digits. If the sum is divisible by 9, then the number is divisible by 9. So 519 -> 5 + 1 + 9 = 15, which is not a multiple of nine. This 'trick' works on divisible by 9 and also divisible by 3, so 519 is divisible by 3, since 5 + 1 + 9 = 15, which is a multiple of 3. Yes. The result is a fraction though.
1,557 is divisible by 1 and itself, as well as: 3, 9, 173, 519.
Not evenly because it will have a remainder of 3
no4 is an even number and only goes into other even number519 is an odd number so not divisible by 4 exactlyon a calculator 519/4 = 129.75
519
All numbers are divisible by 1.
No. It is also divisible by 3, as you will see if you add the digits of the number together.
Prime numbers are divisible because any numbers that are divisible are prime. If a number isn't divisible, it isn't prime. Prime numbers have to be divisible by at least one pair of numbers to be prime.
All whole numbers are divisible. If you mean divisible by numbers other than 1 and themselves, the answer is the set of composite numbers.