There is an infinite number of numbers that are divisible by 430.
To find the sum of the numbers 70, 164, 430, and 525 that are divisible by 5, we first identify which numbers meet this criterion. The numbers 70, 430, and 525 are divisible by 5. Their sum is 70 + 430 + 525 = 1025. The number 164 is not included since it is not divisible by 5.
1 + 3 + 5 + ... + 857 + 859 = 184900
is 90,005 divisibly by 2,3,5,9,and10
17% of 430= 17% * 430= 0.17 * 430= 73.1
85% of 430 = 85% * 430 = 0.85 * 430 = 365.5
374 + 56 = 430
The greatest common factor of the numbers 430 and 4 is 2.
(508) = 2 * (254) (254) = 2 * 127 so, prime factors are 2,2 and 127 so, numbers it will divide by are 2 and 127
The greatest common factor of the numbers 162 and 430 is 2.
It is divisibly by 5 and 15.
331.5
There are infinitely many possible answers.400 and 30 and 0, added together is one possible answer;43 and 10 and 1 multiplied together is another.
430
No, 2,990 divided by 20 is 149.5
There are 114 of them.
3= 3,6,9,12,15,18 (6 of them) 4= 4,8,12,16,20 (5 of them) 6+5=11 But only 1 number (12) divisibly by both.
If the average of 5 numbers is 86, then their sum is 430.If the average of 6 numbers is 84, then their sum is 504.The sum grew by (504 - 430) = 74, so that was the 6th number.