The numbers: {1, 2, 4, 12, 14, 21, 24, 41, 42, 124, 142, 214, 241, 412, 421}.
If repeats are allowed, the above plus: {11, 22, 44, 111, 222, 444} plus infinitely many more by preceding the numbers given so far by various combinations of {1, 2, 4} in 1, 2, 3, ... digit groups making 4, 5, 6, ... digit numbers.
45
9*9*9 = 729 using the digits 1 to 9 and 2*9 using 10 and another digit. 749 in all.
To create the numbers 1-100 using the digits 2, 0, 1, and 2, you can use various combinations and operations. For example, you can form numbers like 1 (by using 2-2+1), 2 (using one of the 2s), 10 (by combining 2 and 0), and higher numbers such as 20 or 21. By creatively using addition, subtraction, and combinations of the digits, you can generate many numbers up to 100. However, some numbers may not be possible with the given digits and operations.
9915 1159 5555 9999 1111
A binary number consists of two possible digits: 0 and 1. When using seven digits, each digit can independently be either 0 or 1. Therefore, the total number of binary numbers that can be formed with seven digits is (2^7), which equals 128. Thus, there are 128 different binary numbers that can be written using seven digits.
45
9*9*9 = 729 using the digits 1 to 9 and 2*9 using 10 and another digit. 749 in all.
Using only arrangements of the given digits: without repeating digits, 15. with repetition, 39. The answer does not include numbers such as 2^3 = 8 or 3^(2+1) = 27
To create the numbers 1-100 using the digits 2, 0, 1, and 2, you can use various combinations and operations. For example, you can form numbers like 1 (by using 2-2+1), 2 (using one of the 2s), 10 (by combining 2 and 0), and higher numbers such as 20 or 21. By creatively using addition, subtraction, and combinations of the digits, you can generate many numbers up to 100. However, some numbers may not be possible with the given digits and operations.
9915 1159 5555 9999 1111
A binary number consists of two possible digits: 0 and 1. When using seven digits, each digit can independently be either 0 or 1. Therefore, the total number of binary numbers that can be formed with seven digits is (2^7), which equals 128. Thus, there are 128 different binary numbers that can be written using seven digits.
25 digits
6
To calculate the number of four-digit numbers that can be made using the digits 1, 4, 5, and 9 without repetition, we use the permutation formula. Since there are 4 digits to choose from for the first digit, 3 for the second, 2 for the third, and 1 for the fourth, the total number of permutations is 4 x 3 x 2 x 1 = 24. Therefore, there are 24 different four-digit numbers that can be formed using the digits 1, 4, 5, and 9 without repetition.
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
18 can.
162