378.
t(n) = (21n3 - 142n2 + 359n - 114)/2 for n = 1, 2, 3, etc
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4.2, 9, 28, 65, 126, ____ what is next
127, 131, 137, 139, 149 and 151.
The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.
There are actually nine numbers: 102, 114, 126, 138, 150, 162, 174, 186 and 198.
12.6*10 = 126 = 1.26*102