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If the dimensions are restricted to whole numbers, then the only possibilities are 1 x 4 and 2 x 3.
The perimeter of a rectangle is the sum of its 4 sides added together.
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
6 in by 8 in by 10 in.
If the dimensions are restricted to whole numbers, then the only possibilities are 1 x 4 and 2 x 3.
Ah, what a lovely question! To find the perimeter of a rectangle, we need to know both the length and width. Since the area is 432 square feet, we can find the dimensions by factoring 432 into pairs of numbers until we find a pair that could be the length and width of the rectangle. Once we have the dimensions, we can simply add up all the sides to find the perimeter.
The perimeter of a rectangle is the sum of its 4 sides added together.
Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm
In whole numbers, the greatest perimeter would be a rectangle 48 x 1, resulting in a perimeter of 98m.
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
Let x and y be the dimensions of the rectangle. Therefore, x+y=107 and x*y=2310. The question is the find two real numbers such that they satisfy the above statement. There are x=77 and y=32 that satisfy the statement above
6 in by 8 in by 10 in.
Any number between 0 and 12 that you like. There is no need for the sides of the rectangle to be whole numbers!
The perimeter of a rectangle is always even because the perimeter is twice the length plus twice the width. Whenever you multiply a number by 2, the product is even. When you add two even numbers the sum is even.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
Simple the Perimeter you just add the outside numbers. For area. When I look at an octagon I see a rectangle and two Trapezoids on either side of the rectangle. So find the area of each object then add the areas up and voila you got the area of a rectangle.