HCF(42, 48) = 6
So the answer is 6 and all its factors.
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Any of its factors
1, 2, 3 and 6 all go into both 48 and 114 evenly.
1, 2, 3, and 6 can go into both of them evenly.
The numbers are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
No. 42 is not evenly divisible by four.