247, 494 (=247*2), 741 (=247*3) etc.
There are no two numbers between 10 and 20 with a product of 247.
1, 3, 13, 19, 39, 57, 247, 741.
1 13 19 247.
The two prime numbers 13*19=247
247, 494 (=247*2), 741 (=247*3) etc.
There are no two numbers between 10 and 20 with a product of 247.
The whole number of 247 is between the whole numbers of 246 and 248
It is: 676-247 = 429
1 13 19 247.
1, 3, 13, 19, 39, 57, 247, 741.
The two prime numbers 13*19=247
247 + 398 = 645398 - 247 = 151Therefore the two numbers which add together to make 645 and have a difference of 151 are 247 and 398.
All of the prime numbers (except 2) are odd. The sum of any two prime numbers (except 2) will be even. Unless 245 is a prime number (it isn't) your question does not have a solution.
1, 13, 19, 247.
645 - 151 = 494 494 / 2 = 247 247 + 151 = 398 Which means: 398 + 247 = 645 and 398 - 247 = 151
The numbers are 245, 246 and 247.