The factors of 360 are:
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 72, 90, 120, 180, 360
The factors of 945 are:
1, 3, 5, 7, 9, 15, 21, 27, 35, 45, 63, 105, 135, 189, 315, 945
They are members of the infinite set of numbers of the form 945*k where k is an integer. Since the set is infinite, it is not possible to list them.
3 x 3 x 3 x 5 x 7
945 ÷ 15 = 63.
5 times 189 equals 945. You can tell 945 is composite because it ends in a 5. That means if you keep counting by 5's and you count 5 189 times, you should get 945!
15 goes into 945 63 times.
Two numbers, 155 and 945, do not form a proportion.
907 + 31 + 5 + 2 = 945
They are members of the infinite set of numbers of the form 945*k where k is an integer. Since the set is infinite, it is not possible to list them.
All of these numbers meet those conditions: 135, 180, 225, 270, 315, 360, 405, 450, 495, 540, 585, 630, 675, 720, 765, 810, 855, 900, 945, 990What_3_digit_numbers_are_divisible_by_5_and_9
945/5=189
3 x 3 x 3 x 5 x 7
35*27
945 ÷ 15 = 63.
To find two numbers that multiply to 945, we need to factorize 945 into its prime factors. 945 can be expressed as 3 x 3 x 3 x 5 x 7. Therefore, the two numbers that multiply to 945 are 3 x 3 x 3 x 5 and 7, which simplifies to 27 x 5 and 7. So, the two numbers are 135 and 7.
These numbers: 1, 3, 5, 7, 9, 15, 21, 27, 35, 45, 63, 105, 135, 189, 315, 945.
5 times 189 equals 945. You can tell 945 is composite because it ends in a 5. That means if you keep counting by 5's and you count 5 189 times, you should get 945!
15 goes into 945 63 times.