2 and 6
3 and 4
1 and 12
-2 and -6
-3 and -4
-1 and -12
You should know this really
How about: 1*3*4 = 12
3 pairs 1 times 12, 2 times 6, and 3 times 4
There cannot be such a pair. a2 and b2 when multiplied together give a2b2 = (ab)2 So if two square numbers are multiplied together, their product is a square. 12 is not a square so the two numbers cannot exist.
Their sum is -12
1,3 and 4
There are infinitely many possible answers. One possibility is 120 and 0.1.
The two numbers multiplied are 12*12, 1*144
How about: 1*3*4 = 12
12 and 1
No,because it doesn't make sence for ending numbers multiplied together make an ending number
2 * 66 3 * 44 4 * 33 6 * 22 12*11
3 pairs 1 times 12, 2 times 6, and 3 times 4
There cannot be such a pair. a2 and b2 when multiplied together give a2b2 = (ab)2 So if two square numbers are multiplied together, their product is a square. 12 is not a square so the two numbers cannot exist.
-5 and -7
Their sum is -12
1,3 and 4
19 and 12