2 and 6
3 and 4
1 and 12
-2 and -6
-3 and -4
-1 and -12
You should know this really
How about: 1*3*4 = 12
No two numbers exist.for the two numbers to be added to be negative and multiplied to be positive, both numbers must be negative, and the highest possible multiplication for two numbers added to -12 would be (-6 and -6) but multiplied, yields 36. So, no such numbers would exist.
3 pairs 1 times 12, 2 times 6, and 3 times 4
There cannot be such a pair. a2 and b2 when multiplied together give a2b2 = (ab)2 So if two square numbers are multiplied together, their product is a square. 12 is not a square so the two numbers cannot exist.
Their sum is -12
There are infinitely many possible answers. One possibility is 120 and 0.1.
The two numbers multiplied are 12*12, 1*144
12 and 1
How about: 1*3*4 = 12
No two numbers exist.for the two numbers to be added to be negative and multiplied to be positive, both numbers must be negative, and the highest possible multiplication for two numbers added to -12 would be (-6 and -6) but multiplied, yields 36. So, no such numbers would exist.
No,because it doesn't make sence for ending numbers multiplied together make an ending number
2 * 66 3 * 44 4 * 33 6 * 22 12*11
There cannot be such a pair. a2 and b2 when multiplied together give a2b2 = (ab)2 So if two square numbers are multiplied together, their product is a square. 12 is not a square so the two numbers cannot exist.
3 pairs 1 times 12, 2 times 6, and 3 times 4
-5 and -7
1,3 and 4
Their sum is -12