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All multiples of 486 (which are infinite) including 486, 972, 1458, 1944, 2430 . . .
The LCM is 2430.
population = 30 × 3^(20÷5) = 30 × 3⁴ = 2430
2430 is one
The LCM of two numbers A and B = AB ÷ F, where F is the GCF For this question, AB = 270 x 9 = 2430 We now need to find a set of paired factors of 2430 such that both numbers are divisible by 9. So, just taking one of the pair as being a multiple of 9 then :- 270 x 9......Yes 135 x 18....Yes 90 x 27......Yes 67.5 x 36....No 54 x 45......Yes.........which is as far as we need to check. So there are four pairs of numbers satisfying the given conditions : 270 & 9, 135 & 18, 90 & 27 and 45 & 54.